NCERT Solutions Class 8 Maths Chapter 3 Understanding Quadrilaterals Exercise 3.3

Understanding Quadrilaterals

Exercise 3.3

1). Given a parallelogram ABCD. Complete each statement along with the definition or property used.

(i) AD = …… (ii) Ð DCB = ……

(iii) OC = …… (iv) m Ð DAB + m Ð CDA = ……

Answer:

(i) AD = BC

The opposite sides of a parallelogram are congruent.

(ii) Ð DCB = Ð DAB

The opposite angles of a parallelogram are congruent.

(iii) OC = OA

The diagonals of a parallelogram bisect each other.

(iv) m Ð DAB + m Ð CDA = 1800

The adjacent angles of a parallelogram are supplementary.

2). Consider the following parallelograms. Find the values of the unknowns x, y, z.

(i) The adjacent angles of a parallelogram are supplementary.

Ð ABC + Ð BCD = 1800

1000 + x = 1800

x = 180 – 100

x = 800

the opposite angles of a parallelogram are congruent

Ð ADC = Ð ABC

but Ð ABC = 1000

Ð ADC = y = 1000

Similarly ÐBCD = ÐBAD

but Ð BCD = 800

Ð BAD = z = 800                  

(ii)

The adjacent angles of a parallelogram are supplementary.

500 + x = 1800

 x = 1800  – 500

x = 1300

the opposite angles of a parallelogram are congruent

x = y

but x = 1300

y = 1300

z and x are corresponding angles  

 z = x

but x = 1300

z = 1300       

(iii)

diagonals are intersecting at right angles

The given quadrilateral is a rhombus

x = 900                                              vertically opposite angles

 

x + y + 300 = 1800              angle sum property of triangle

900 + y + 300 = 1800

y + 1200 = 1800

y = 1800 – 1200

y = 600

z = y                                        alternate angles

but y = 600

z = 600  

 

(iv)

The adjacent angles of a parallelogram are supplementary.

800 + x = 1800

 x = 1800 – 800

x = 1000

the opposite angles of a parallelogram are congruent

y = 800

z = y                                      alternate angles

but y = 800

z = 800         

 

 (v)

the opposite angles of a parallelogram are congruent

y = 1120 

x + y + 400 = 1800              angle sum property of triangle

x + 1120 + 400 = 1800

x + 1520 = 1800

x = 1800 – 1520

x = 280

z = x                                      alternate angles

but x = 280

z = 280         

3). Can a quadrilateral ABCD be a parallelogram if

(i) Ð D + Ð B = 180°?

(ii) AB = DC = 8 cm, AD = 4 cm and BC = 4.4 cm?

(iii) Ð A = 70° and Ð C = 65°?

Solution:

(i) Ð D + Ð B = 180°?

A quadrilateral can be a parallelogram if

i). The opposite angles are congruent and

ii). The adjacent angles are supplementary

as the information is incomplete

ABCD may or may not be a parallelogram

(ii) AB = DC = 8 cm, AD = 4 cm and BC = 4.4 cm?

A quadrilateral can be a parallelogram if the opposite sides are congruent

Here AB = DC  but AD ≠ BC

ABCD is not a parallelogram

(iii) Ð A = 70° and Ð C = 65°?

A quadrilateral can be a parallelogram if the opposite angles are congruent

ÐA  ≠ ÐC

ABCD is not a parallelogram

4). Draw a rough figure of a quadrilateral that is not a parallelogram but has exactly two opposite angles of equal measure.

5). The measures of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measure of each of the angles of the parallelogram.

Let the common multiple be x

The measures of the two adjacent angles are 3x and 2x

The adjacent angles of a parallelogram are supplementary

3x + 2x = 1800

5x = 1800

x = 180/5

x = 360

3x = 3 X 36 = 1080

2x = 2 X 36 = 720

6). Two adjacent angles of a parallelogram have equal measure. Find the measure of each of the angles of the parallelogram.

Let the two equal adjacent angles be x

The adjacent angles of a parallelogram are supplementary

x + x = 1800

2x = 1800

x = 180/2

x = 900

opposite angles of parallelogram are equal

therefore, each of the angle of parallelogram is 900

7). The adjacent figure HOPE is a parallelogram. Find the angle measures x, y and z. State the properties you use to find them.

y = 400                               alternate angles

 

y + z = 700                         Exterior angle property

400 + z = 700

z = 700 – 400

z = 300

ÐPOH + 700 = 1800                    linear pair

ÐPOH  = 1800 – 700

ÐPOH  = 1100

ÐPOH = x                           opposite angles

x = 1100

 

8). The following figures GUNS and RUNS are parallelograms. Find x and y. (Lengths are in cm)

i).

opposite sides of a parallelogram are congruent

GS = UN and GU = SN

GS = UN

3x = 18

x = 18/3

x = 6 cm

GU = SN

3y – 1 = 26

3 y = 26 + 1

3 y = 27

y = 27/3

y = 9 cm

ii).

The diagonals of a parallelogram bisect each other

x + y = 16 and y + 7 = 20

y + 7 = 20

y  = 20 – 7

y  = 13 cm

x + y = 16

x + 13 = 16

x  = 16 – 13

x  = 3 cm

9). In the above figure both RISK and CLUE are parallelograms. Find the value of x.

Adjacent angles of a parallelogram are supplementary

ÐRKS + ÐKSI = 1800

1200 + ÐKSI = 1800

ÐKSI = 1800 – 1200

ÐKSI = 600

Similarly, ÐCLU = ÐUEC                            opposite angles of parallel

ÐUEC = 700

700 + 600 + x = 1800

1300 + x = 1800

x = 180– 1300

x = 500

 10). Explain how this figure is a trapezium. Which of its two sides are parallel? (Fig 3.26)

ÐM + ÐN = 1000 + 800 = 1800

One pair of adjacent angles are supplementary

□KLMN is trapezium

KL II MN

 

11). Find mÐC in Fig 3.27 if AB II DC.

AB II DC and BC is transversal

ÐB + ÐC = 1800                                  interior angles

1200 + ÐC = 1800

ÐC = 1800 – 1200

ÐC = 600

 12). Find the measure of ÐP and ÐS if SP II RQ in Fig 3.28. (If you find mÐR, is there more than one method to find mÐP?)

SP II RQ and SR is transversal

ÐR + ÐS = 1800                                   interior angles

900 + ÐS = 1800

ÐS = 1800 – 900

ÐS = 900 

ÐP + ÐQ + ÐR + ÐS = 3600                              

the sum of the angles of a quadrilateral is 3600

ÐP + 1300+ 900 + 900 = 3600

ÐP + 3100 = 3600

ÐP = 3600 – 3100

ÐS = 500

Click here for the solutions of Std 8 Maths

1). Rational Numbers

 Exercise 1.1

2). Linear Equations in One Variable

Exercise 2.1

Exercise 2.2

3). Understanding Quadrilaterals

Exercise 3.1

Exercise 3.2

Exercise 3.3

Exercise 3.4

4). Data Handling

Exercise 4.1

Exercise 4.2

 

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