Algebraic Expressions Exercise 12.1 1). Get the algebraic expressions in the following cases using variables, constants and arithmetic operations. (i) Subtraction of z from y. (ii) One-half of the sum of numbers x and y. (iii) The number z multiplied by itself. (iv) One-fourth of the product of numbers p and q. (v) Numbers x and …
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Comparing Quantities Exercise 8.2 1). Convert the given fractional numbers to per cents. (a) 1/8 (b) 5/4 (c) 3/40 (d) 2/7 Solution: (a) 1/8 (b) 5/4 (c) 3/40 (d) 2/7 2). Convert the given decimal fractions to per cents. (a) 0.65 (b) 2.1 (c) 0.02 (d) 12.35 Solution: (a) 0.65 0.65 = …
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Comparing Quantities Exercise 8.1 1). Find the ratio of: (a) ₹ 5 to 50 paise (b) 15 kg to 210 g (c) 9 m to 27 cm (d) 30 days to 36 hours Solution: (a) ₹5 to 50 paise ₹ 5 = 500 paise ₹ 5 : 50 paise = 500 paise: 50 …
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Congruence of Triangles Exercise 7.2 1). Which congruence criterion do you use in the following? (a) Given: AC = DF AB = DE BC = EF So, DABC @ DDEF Ans: DABC @ DDEF by SSS rule (b) Given: ZX = RP RQ = ZY ÐPRQ = ÐXZY So, DPQR @ DXYZ Ans: DPQR @ …
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Congruence of Triangles Exercise 7.1 1). Complete the following statements: (a) Two line segments are congruent if they have the same length. (b) Among two congruent angles, one has a measure of 70°; the measure of the other angle is 70°. (c) When we write ÐA = ÐB, we actually mean mÐA = mÐB. …
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The Triangle and Its Properties Exercise 6.5 1). PQR is a triangle, right-angled at P. If PQ = 10cm and PR = 24 cm, find QR. In DPQR, By Pythagorean Property QR2 = PQ2 + PR2 QR2 = 102 + 242 QR2 = 100 + 576 QR2 = 676 Taking square root on both sides …
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The Triangle and Its Properties Exercise 6.4 1). Is it possible to have a triangle with the following sides? (i) 2 cm, 3 cm, 5 cm (ii) 3 cm, 6 cm, 7 cm (iii) 6 cm, 3 cm, 2 cm Solution: (i) 2 cm, 3 cm, 5 cm The sum of the lengths of …
NCERT Solutions Class 7 Maths Chapter 6 The Triangle and Its Properties Exercise 6.4 Read More »